Question:
A process has $\Delta \mathrm{H}=200 \mathrm{Jmol}^{-1}$ and
$\Delta \mathrm{S}=40 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$. Out of the values given below, choose the minimum temperature above which the process will be spontaneous :
Correct Option: 1
Solution:
$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}$
$\mathrm{T}=\frac{\Delta \mathrm{H}}{\Delta \mathrm{S}}=\frac{200}{40}=5 \mathrm{~K}$
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