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A reactant (A) forms two products :

Question:

A reactant (A) forms two products :

$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{B}$, Activation Energy $\mathrm{Ea}_{1}$

$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{C}$, Activation Energy $\mathrm{Ea}_{2}$

If $\mathrm{Ea}_{2}=2 \mathrm{Ea}_{1}$, then $\mathrm{k}_{1}$ and $\mathrm{k}_{2}$ are related as :-

  1. $\mathrm{k}_{1}=2 \mathrm{k}_{2} \mathrm{e}^{\mathrm{Ea}_{2} / \mathrm{RT}}$

  2. $\mathrm{k}_{1}=\mathrm{k}_{2} \mathrm{e}^{\mathrm{Ea}_{1} / \mathrm{RT}}$

  3. $\mathrm{k}_{2}=\mathrm{k}_{1} \mathrm{e}^{\mathrm{Ea}_{2} / \mathrm{RT}}$

  4. $\mathrm{k}_{1}=\mathrm{A} \mathrm{} \mathrm{k}_{2} \mathrm{e}^{\mathrm{Ea}_{1} / \mathrm{RT}}$


Correct Option: 1

Solution:

$\mathrm{k}_{2}=\mathrm{k}_{1}(2)^{5}=32 \mathrm{k}_{1}$

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