Question:
A series LCR circuit is designed to resonate at an angular frequency $\omega_{0}=10^{5} \mathrm{rad} / \mathrm{s}$.
The circuit draws $16 \mathrm{~W}$ power from $120 \mathrm{~V}$ source at resonance. The value of
resistance ' $\mathrm{R}^{\prime}$ in the circuit is $\Omega$
Solution:
(900)
$P=\frac{V^{2}}{R}$
$16=\frac{120^{2}}{R} \Rightarrow R=\frac{14400}{16}$
$\Rightarrow R=900 \Omega$
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