Question:
A solenoid of 1000 turns per metre has a core with relative permeability
500 . Insulated windings of the solenoid carry an electric current of $5 \mathrm{~A}$.
The magnetic flux density produced by the solenoid is:
(permeability of free space $=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}$ )
Correct Option:
Solution:
(1)
$\mathrm{B}=\mu \mathrm{nI}=\mu_{0} \mu_{\mathrm{rn}} \mathrm{I}$
$\mathrm{B}=4 \pi \times 10^{-7} \times 500 \times 1000 \times 5$
$\mathrm{~B}=\pi$ Tesla
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