Question:
A solution is prepared by dissolving $0.6 \mathrm{~g}$ of urea (molar mass $=60 \mathrm{~g} \mathrm{~mol}^{-1}$ ) and $1.8 \mathrm{~g}$ of glucose (molar mass $=180 \mathrm{~g} \mathrm{~mol}^{-1}$ ) in $100 \mathrm{~mL}$ of water at $27^{\circ} \mathrm{C}$. The osmotic pressure of the solution is:
$\left(\mathrm{R}=0.08206 \mathrm{~L}\right.$ atm $\left.\mathrm{K}^{-1} \mathrm{~mol}^{-1}\right)$
Correct Option: 1
Solution:
$\Pi=\frac{\left(\frac{0.6}{60}+\frac{1.8}{180}\right)}{0.1} \times 0.08206 \times 300$
$\Pi=4.9236 \mathrm{~atm}$