A sphere, a cylinder, and a cone have the same diameter.

Let r be the common radius

Height of the cone = height of the cylinder = 2r

Let

$y_{1}=$ Volume of sphere $=4 / 3 \pi r^{3}$

$\mathrm{v}_{1}=$ Volume of cylinder $=\pi r^{2} \mathrm{~h}=\pi r^{2} \times 2 r$

$v_{1}=$ Volume of cone $=1 / 3 \pi r^{2} h=1 / 3 \pi r^{3}$

Now

$v_{1}: v_{2}: v_{3}=4 / 3 \pi r^{3}: 2 \pi r^{3}: 2 / 3 \pi r^{3}$

= 4:6:2 = 2:3:1