A straight line moves so that the sum

Question:

A straight line moves so that the sum of the reciprocals of its intercepts made on axes is constant. Show that the line passes through a fixed point.

Solution:

We know that intercepts form of a straight line is

$\frac{x}{a}+\frac{y}{b}=1$

Where $a$ and $b$ are the intercepts on the axes

Given that $\frac{1}{a}+\frac{1}{b_{k}}=\frac{1}{k}$ (let)

On cross multiplication we get

$\Rightarrow \frac{k}{a}+\frac{k}{b}=1$

This shows that the line is passing through the fixed point ( $k, k$ )

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