Question:
A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m. The height of the cylindrical portion is 11m while the vertex of the cone is 16 m above the ground. Find the area of the canvas required for the tent.
Solution:
It is given that
Diameter of cylinder = 24 m
there fore radius = daimeter/2
= 24/2 = 12 cm
Also radius of cone = 12 m
Height of cylinder = 11 m
Height of cone = 16 - 11 = 5 m
Slant height of cone
$=\sqrt{5^{2}+12^{2}}$
= 13 m
Therefore area of canvas required for the tent = πrl + 2πrh
= 22/7 [(12 ∗ 13) + (2 ∗ 12 ∗ 11)] = 490.286 + 829.714
$=1320 \mathrm{~m}^{2}$
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