A train travels 360 km at a uniform speed. If the speed had been 5 km/hr more,

Let us assume that the speed of the train be ‘x’ km/hr. We are also given that the distance covered during the journey is 360 km.

Now, time taken during the journey $=\left(\frac{360}{x}\right) \mathrm{hr}$

Time taken for the new journey $=\left(\frac{360}{x+5}\right) \mathrm{hr}$

According to the question,

$\left(\frac{360}{x}\right)-\left(\frac{360}{x+5}\right)=1$

$\left(\frac{360 x+1800-360 x}{x^{2}+5 x}\right)=1$

$x^{2}+5 x=1800$

$x^{2}+5 x-1800=0$

Hence, this is the required quadratic equation.