A wall 24 m long, 0.4 m thick and 6 m high is constructed

Solution:

Given that, a wall is constructed with the help of bricks and mortar.

$\therefore$  Number of bricks $=\frac{\text { (Nolume of wall) }-\left(\frac{1}{10} \text { th volume of wall }\right)}{\text { Volume of a brick }}$...(i)

Also, given that

Length of a wall $(l)=24 \mathrm{~m}$,

Thickness of a wall $(b)=0.4 \mathrm{~m}$,

 

Height of a wall $(h)=6 \mathrm{~m}$

So, volume of a wall constructed with the bricks $=l \times b \times h$

$=24 \times 0.4 \times 6=\frac{24 \times 4 \times 6}{10} \mathrm{~m}^{3}$

Now,$\frac{1}{10}$ th volume of a wall $=\frac{1}{10} \times \frac{24 \times 4 \times 6}{10}=\frac{24 \times 4 \times 6}{10^{2}} \mathrm{~m}^{3}$

and Length of a brick $\left(l_{l}\right)=25 \mathrm{~cm}=\frac{25}{100} \mathrm{~m}$

Breadth of a brick $\left(b_{1}\right)=16 \mathrm{~cm}=\frac{16}{100} \mathrm{~m}$

Height of a brick $\left(h_{1}\right)=10 \mathrm{~cm}=\frac{10}{100} \mathrm{~m}$

So, volume of a brick $=l_{1} \times b_{1} \times l_{1}$

$=\frac{25}{100} \times \frac{16}{100} \times \frac{10}{100}=\frac{25 \times 16}{10^{5}} \mathrm{~m}^{3}$

From Eq. (i),

Number of bricks $=\frac{\left(\frac{24 \times 4 \times 6}{10}-\frac{24 \times 4 \times 6}{100}\right)}{\left(\frac{25 \times 16}{10^{5}}\right)}$

$=\frac{24 \times 4 \times 6}{100} \times 9 \times \frac{10^{5}}{25 \times 16}$

$=\frac{24 \times 4 \times 6 \times 9 \times 1000}{25 \times 16}$

$=24 \times 6 \times 9 \times 10=12960$

Hence, the required number of bricks used in constructing the wall is 12960.