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Class 9-10, JEE & NEET
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ΔABC can be constructed in which BC = 6 cm, ∠C = 30° and AC – AB =4 cm.
We know that, a triangle can be constructed if sum of its two sides is greater than third side.
i.e., in ΔABC, AB + BC > AC
=> BC > AC – AB
=> 6 > 4, which is true, so ΔABC with given conditions can be constructed.