ABCD is a parallelogram in which ∠A = 70°.


ABCD is a parallelogram in which ∠A = 70°. Compute ∠BC and D.


Opposite angles of a parallelogram are equal.

$\therefore \angle \mathrm{C}=70^{\circ}=\angle \mathrm{A} .$

$\angle \mathrm{B}=\angle \mathrm{D}$

Also, the sum of the adjacent angles of a parallelogram is $180^{\circ}$.

$\therefore \angle \mathrm{A}+\angle \mathrm{B}=180^{\circ}$

$70^{\circ}+\angle \mathrm{B}=180^{\circ}$

$\angle \mathrm{B}=110^{\circ}$

$\therefore \angle \mathrm{B}=110^{\circ}, \angle \mathrm{C}=70^{\circ}$ and $\angle \mathrm{D}=110^{\circ}$

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