According to Bohr’s atomic theory :

According to Bohr’s atomic theory :

(A) Kinetic energy of electron is $\propto \frac{\mathrm{Z}^{2}}{\mathrm{n}^{2}}$

(B) The product of velocity (v) of electron and principal quantum number (n). ‘vn’ $\propto \mathrm{Z}^{2}$.

(C) Frequency of revolution of electron in an orbit is $\propto \frac{Z^{3}}{n^{3}}$.

(D) Coulombic force of attraction on the electron is $\propto \frac{Z^{3}}{n^{4}}$. Choose the most appropriate answer from the options given below:

  1. (C) only

  2. (A) and (D) only

  3. (A) only

  4. (A), (C) and (D) only

Correct Option: , 2


(A) $\mathrm{KE}=-\mathrm{TE}=13.6 \times \frac{\mathrm{Z}^{2}}{\mathrm{n}^{2}} \mathrm{eV}$

$=K \mathrm{E} \propto \frac{\mathrm{Z}^{2}}{\mathrm{n}^{2}}$

(B) $V=2.188 \times 10^{6} \times \frac{\mathrm{z}}{\mathrm{n}} \mathrm{m} / \mathrm{sec}$

So, $\mathrm{Vn} \propto Z$

(C) Frequency $=\frac{\mathrm{V}}{2 \pi_{\mathrm{r}}}$

So, $\mathrm{F} \propto \frac{\mathrm{Z}^{2}}{\mathrm{n}^{3}}$

$\left[\therefore r \propto \frac{n^{2}}{z}\right.$ and $\left.\vee \propto \frac{z}{n}\right]$

(D) Force $\propto \frac{\mathrm{z}}{\mathrm{r}^{2}}$

So, $F \propto \frac{Z^{3}}{n^{4}}$

So, only statement (A) is correct


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