Among the following, the energy of
Question:

Among the following, the energy of $2 \mathrm{~s}$ orbital is lowest in :

  1. K

  2. H

  3. Li

  4. Na


Correct Option: 1

Solution:

As the value of $Z$ (atomic number) increases, energy of orbitals decreases (becomes more -ve value)

$\therefore$ Order of energy of $2 s$ orbital is $\mathrm{H}>\mathrm{Li}>\mathrm{Na}>\mathrm{K}$.

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