Question:
An aeroplane covers $1020 \mathrm{~km}$ in an hour. How much distance will it cover in $4 \frac{1}{6}$ hours?
Solution:
Distance covered by the aeroplane in $4 \frac{1}{6}$ hours $=4 \frac{1}{6} \times 1020$
$=\left(4+\frac{1}{6}\right) \times 1020$
$=\frac{25}{6} \times 1020$
$=\frac{25}{6} \times \frac{1020}{1}$
$=\frac{25 \times 1020}{6 \times 1}$
$=\frac{25500}{6}$
$=4250 \mathrm{~km}$
Therefore, the distance covered by the aeroplane is $4250 \mathrm{~km}$.