An electron is constrained to move along the $y$-axis with a speed of $0.1 c$ ( $c$ is the speed of light) in the presence of electromagnetic wave, whose electric field is $\vec{E}=30 \hat{j}$ $\sin \left(1.5 \times 10^{7} t-5 \times 10^{-2} x\right) \mathrm{V} / \mathrm{m}$. The maximum magnetic force experienced by the electron will be :
(given $c=3 \times 10^{8} \mathrm{~ms}^{-1} \&$ electron charge $\left.=1.6 \times 10^{-19} \mathrm{C}\right)$
Correct Option: , 3
(3) In electromagnetic wave, $\frac{E_{0}}{B_{0}}=C$
$\therefore$ Maximum value of magnetic field, $B_{0}=\frac{E_{0}}{C}$
$F_{\max }=q V B_{\max } \sin 90^{\circ}=\frac{q V_{0} E_{0}}{C}$
(Given $V_{0}=0.1 \mathrm{C}$ and $E_{0}=30$ )
$=\frac{1.6 \times 10^{-19} \times 0.1 \times 3 \times 10^{8} \times 30}{3 \times 10^{8}}=4.8 \times 10^{-19} \mathrm{~N}$
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