An element placed in 2nd group and 3rd Period of the Periodic Table,

Question:

An element placed in 2nd group and 3rd Period of the Periodic Table, burns in the presence of oxygen to form a basic oxide.

(a) Identify the element

(b) Write the electronic configuration

(c) Write the balanced equation when it burns in the presence of air

(d) Write a balanced equation when this oxide is dissolved in water

(e) Draw the electron dot structure for the formation of this oxide

Solution:

(a) The element is magnesium (Mg).

(b) The electronic configuration is 2, 8, 2.

(c) Magnesium burns in oxygen (air) to form magnesium oxide which is of basic nature.

2Mg(s) + O2(g) ————-> 2MgO(s)

(d) Magnesium hydroxide is formed.

MgO(s) + H2O(aq) ————> Mg(OH)2(s)

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now