Question:
An LCR circuit contains resistance of $110 \Omega$ and a supply of $220 \mathrm{~V}$ at $300 \mathrm{rad} / \mathrm{s}$ angular frequency. If only capacitance is removed from the
circuit, current lags behind the voltage by $45^{\circ}$. If on the other hand, only inductor is removed the current leads by $45^{\circ}$ with the applied
voltage. The rms current flowing in the circuit will be:
Correct Option: , 2
Solution:
(2)
Since $\phi$ remain same, circuit is in resonance
$\therefore \mathrm{I}_{\mathrm{rms}}=\frac{\mathrm{V}_{\mathrm{rms}}}{\mathrm{z}}$
$=\frac{220}{110}$
$\mathrm{I}_{\mathrm{rms}}=2 \mathrm{~A}$
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