An object is placed at a distance of
Question:

An object is placed at a distance of $12 \mathrm{~cm}$ from a convex lens. A convex mirror of focal length $15 \mathrm{~cm}$ is placed on other side of lens at $8 \mathrm{~cm}$ as shown in the figure. Image of object coincides with the object.

When the convex mirror is removed, a real and inverted image is formed at a position. The distance of the image from the object will be . (cm)

 

 

Solution:

For the object to coincide with image, the light must fall perpendicularly to mirror. Which means that the light will have to converge at $\mathrm{C}$ of mirror. Without the mirror also, the light would coverage at $\mathrm{C}$.

So the distance is : $12+8+30=50 \mathrm{~cm}$

 

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