Apoorv throws two dice once and computes

Question:

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that

appears on it. Who has the better chance of getting the number 36? Why?

Solution:

Apoorv throws two dice once.

So total number of outcomes = 36

Number of outcomes for getting product 36 = 1 (6 x 6)

$\therefore \quad$ Probability for Apoorv $=\frac{1}{36}$

Also, Peehu throws one die,

 

So, total number of outcomes $=6$

Number of outcomes for getting square $36=1\left(6^{2}=36\right)$

$\therefore \quad$ Probability for Peehu $=\frac{1}{6}=\frac{6}{36}$

Hence, Peehu has better chance of getting the number 36.

 

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