Question:
At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ}$. Find the true dip :
Correct Option: , 4
Solution:
$A \tan \delta=\tan \delta^{\prime} \cos \theta$
$=\tan 45^{\circ} \cos 30^{\circ}$
$\tan \delta=1 \times \frac{\sqrt{3}}{2}$
$\delta=\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)$
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