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At an angle of 30° to the magnetic meridian,

Question:

At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ}$. Find the true dip :

  1. $\tan ^{-1} \sqrt{3}$

  2. $\tan ^{-1} \frac{1}{\sqrt{3}}$

  3. $\tan ^{-1} \frac{2}{\sqrt{3}}$

  4. $\tan ^{-1} \frac{\sqrt{3}}{2}$


Correct Option: , 4

Solution:

$A \tan \delta=\tan \delta^{\prime} \cos \theta$

$=\tan 45^{\circ} \cos 30^{\circ}$

$\tan \delta=1 \times \frac{\sqrt{3}}{2}$

$\delta=\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)$

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