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At room temperature, a dilute soluton of urea is prepared by dissolving

Question:

At room temperature, a dilute soluton of urea is prepared by dissolving $0.60 \mathrm{~g}$ of urea in $360 \mathrm{~g}$ of water. If the vapour pressure of pure water at this temperature is $35 \mathrm{mmHg}$, lowering of vapour pressure will be (molar mass of urea $=60 \mathrm{~g} \mathrm{~mol}^{-1}$ ):-

  1. $0.027 \mathrm{mmHg}$

  2. $0.028 \mathrm{mmHg}$

  3. $0.017 \mathrm{mmHg}$

  4. $0.031 \mathrm{mmHg}$

Correct Option: , 3

Solution:

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