Question:
Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that β4 for this complex is 2.1 × 1013.
Solution:
β4 = 2.1 × 1013
The overall complex dissociation equilibrium constant is the reciprocal of the overall stability constant, β4.
$\therefore \frac{1}{\beta_{4}}=\frac{1}{2.1 \times 10^{13}}$
$=4.7 \times 10^{-14}$
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