Calculate the volume occupied by 8.8 g of CO2 at 31.1°C and 1 bar pressure.

It is known that,

$p V=\frac{m}{M} \mathrm{RT}$

$\Rightarrow V=\frac{m \mathrm{R} T}{M p}$

Here,

m = 8.8 g

R = 0.083 bar LK–1 mol–1

T = 31.1°C = 304.1 K

M = 44 g

p = 1 bar

Thus, volume $(V)=\frac{8.8 \times 0.083 \times 304.1}{44 \times 1}$

$=5.04806 \mathrm{~L}$

$=5.05 \mathrm{~L}$

Hence, the volume occupied is 5.05 L.