Question:
Can reflection result in plane-polarized light if the light is incident on the interface from the side with higher refractive index?
Solution:
When the angle of incidence is equal to the Brewster’s angle such that the transmitted light is polarized and reflected light is plane-polarized. Following is the equation:
$\operatorname{tani}_{B}=\mu_{2}^{1}=\frac{\mu_{2}}{\mu_{1}}$
Such that μ2 < μ1
When the light travels in a medium, the critical angle is given as
$\operatorname{sini}_{C}=\frac{\mu_{2}}{\mu_{1}}$
Where μ2 < μ1
So, it can be said that |tan iB| > |sin iC| when iB < iC.
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