Question:
(A) $\mathrm{HOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{Cl}^{-}+\mathrm{O}_{2}$
(B) $\mathrm{I}_{2}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{OH}^{-} \rightarrow 2 \mathrm{I}^{-}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
Choose the correct option.
Correct Option: , 3
Solution:
When $\mathrm{H}_{2} \mathrm{O}_{2}$ acts a reducing agent it liberates the $\mathrm{O}_{2}$.
$\mathrm{H}_{2} \mathrm{O}_{2} \rightleftharpoons 2 \mathrm{H}^{+}+\mathrm{O}_{2}+2 \mathrm{e}^{-}$
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