Question:
Conside the following reactions :
$\mathrm{NaCl}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{SO}_{4}$ (Conc.) $\rightarrow$ (A) $+$ Side
products
(A) $+\mathrm{NaOH} \rightarrow$ (B) $+$ Side product
(B) $+\mathrm{H}_{2} \mathrm{SO}_{4}$ (dilute $)+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow$ (C) $+$ Side
product
The sum of the total number of atoms in one molecule each of (A), (B) and (C) is
Solution:
