Consider the line L given by the equation


Consider the line $L$ given by the equation $\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1} .$ Let $Q$ be the mirror image of the point $(2,3,-1)$ with respect to $L$. Let a plane $P$ be such that it passes through $Q$, and the line $L$ is perpendicular to P. Then which of the following points is on the plane $\mathrm{P}$ ?

  1. $(-1,1,2)$

  2. $(1,1,1)$

  3. $(1,1,2)$

  4. $(1,2,2)$

Correct Option: , 4


Plane $p$ is $\perp^{\mathrm{r}}$ to line


\& passes through pt. $(2,3)$ equation of plane $p$


$2 x+y+z-6=0$

pt $(1,2,2)$ satisfies above equation

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