Construct a quadrilateral ABCD in which AB = 2.8 cm,

Steps of construction :

Step I : Draw $\mathrm{AB}=2.8 \mathrm{~cm}$.

Step II : Construct $\angle \mathrm{BAD}=60^{\circ}$.

Step III : With A as the centre and radius $3.3 \mathrm{~cm}$, cut off $\mathrm{AD}=3.3 \mathrm{~cm}$.

Step IV: With D as the centre and radius $2.6 \mathrm{~cm}$, draw an arc.

Step V : With B as the centre and radius $3.1 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at C.

Step VI : Join BC and CD to obtained the required quadrilateral.