Construct a quadrilateral ABCD in which AB = 3.8 cm,

Question:

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

Solution:

Steps of construction :

Step I : Draw $\mathrm{AC}=6 \mathrm{~cm} .$

Step II : With $\mathrm{A}$ as the centre and radius $3.8 \mathrm{~cm}$, draw an arc.

Step III : With $\mathrm{C}$ as the centre and radius $3.0 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step II at B.

Step IV: With B as the centre and radius $3.8 \mathrm{~cm}$, draw an arc on the other side of AC.

Step V : With A as the centre and radius $2.3 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at D.

Step VI : Join BA, DA, BC and CD to obtained the required quadrilateral.

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now