Construct a quadrilateral ABCD in which AB = 7.7 cm,


Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AD = 3.6 cm and ∠C = 120°.


Steps of construction:

Step I: Draw DC $=5.1 \mathrm{~cm} .$

Step II : Construct $\angle \mathrm{DCB}=120^{\circ}$.

Step III : With C as the centre and radius $6.8 \mathrm{~cm}$, cut off BC $=6.8 \mathrm{~cm} .$

Step IV : With B as the centre and radius $7.7 \mathrm{~cm}$, draw an arc.

Step V : With D as the centre and radius $3.6 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at A.

Step VI : Join $A B$ and $A D$ to obtained the required quadrilateral.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now