Construct a quadrilateral ABCD, in which AB = BC = 3 cm,

Steps of construction:

Step I : Draw $\mathrm{AB}=3 \mathrm{~cm}$.

Step II : Construct $\angle \mathrm{DAB}=90^{\circ}$ at A.

Step III : With A as the centre and radius $5 \mathrm{~cm}$, cut off $\mathrm{AD}=5 \mathrm{~cm}$.

Step IV : Construct $\angle \mathrm{ABC}=105^{\circ}$ at B.

Step V : With B as the centre and radius $3 \mathrm{~cm}$, cut off BC $=3 \mathrm{~cm}$.

Step VI : Join CD.

The quadrilateral so obtained is the required quadrilateral.