Construct a quadrilateral ABCD in which AB = BC = 3 cm,

Question:

Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm, and ∠B = 120°.

Solution:

Steps of construction:

Step I: Draw $\mathrm{AB}=3 \mathrm{~cm} .$

Step II : Construct $\angle \mathrm{ABC}=120^{\circ}$.

Step III : With B as the centre and radius $3 \mathrm{~cm}$, cut off BC $=3 \mathrm{~cm}$.

Step IV : With C as the centre and radius $5 \mathrm{~cm}$, draw an arc.

Step V : With A as the centre and radius $5 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at D.

Step VI : Join AD and CD to obtained the required quadrilateral.

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