Construct a quadrilateral ABCD, in which AD = 3.5 cm,

Question:

Construct a quadrilateral ABCD, in which AD = 3.5 cm, AB = 4.4 cm, BC = 4.7 cm, ∠A = 125° and ∠B = 120°.

Solution:

Steps of construction:

Step I : Draw $\mathrm{AB}=4.4 \mathrm{~cm}$.

Step II : Construct $\angle \mathrm{BAD}=125^{\circ}$ at A.

Step III : With A as the centre and radius $3.5 \mathrm{~cm}$, cut off $\mathrm{AD}=3.5 \mathrm{~cm}$.

Step IV : Construct $\angle \mathrm{ABC}=120^{\circ}$ at B.

Step V : With B as the centre and radius $4.7 \mathrm{~cm}$, cut off $\mathrm{BC}=4.7 \mathrm{~cm}$.

Step VI : Join CD.

The quadrilateral so obtained is the required quadrilateral.

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