Convert the following into basic units
Question.
Convert the following into basic units
(i)28.7 pm
(ii)15.15 pm
(iii)25365 mg
Convert the following into basic units
(i)28.7 pm
(ii)15.15 pm
(iii)25365 mg
Solution:
(i) $28.7 \mathrm{pm}$ :
$1 \mathrm{pm}=10^{-12} \mathrm{~m}$
$\therefore 28.7 \mathrm{pm}=28.7 \times 10^{-12} \mathrm{~m}$
$=2.87 \times 10^{-11} \mathrm{~m}$
(ii) $15.15 \mathrm{pm}$ :
$1 \mathrm{pm}=10^{-12} \mathrm{~m}$
$\therefore 15.15 \mathrm{pm}=15.15 \times 10^{-12} \mathrm{~m}$
$=1.515 \times 10^{-12} \mathrm{~m}$
(iii) $25365 \mathrm{mg}$ :
$1 \mathrm{mg}=10^{-3} \mathrm{~g}$
$25365 \mathrm{mg}=2.5365 \times 10^{4} \times 10^{-3} \mathrm{~g}$
Since,
$1 \mathrm{~g}=10^{-3} \mathrm{~kg}$
$2.5365 \times 10^{1} \mathrm{~g}=2.5365 \times 10^{-1} \times 10^{-3} \mathrm{~kg}$
$\therefore 25365 \mathrm{mg}=2.5365 \times 10^{-2} \mathrm{~kg}$
(i) $28.7 \mathrm{pm}$ :
$1 \mathrm{pm}=10^{-12} \mathrm{~m}$
$\therefore 28.7 \mathrm{pm}=28.7 \times 10^{-12} \mathrm{~m}$
$=2.87 \times 10^{-11} \mathrm{~m}$
(ii) $15.15 \mathrm{pm}$ :
$1 \mathrm{pm}=10^{-12} \mathrm{~m}$
$\therefore 15.15 \mathrm{pm}=15.15 \times 10^{-12} \mathrm{~m}$
$=1.515 \times 10^{-12} \mathrm{~m}$
(iii) $25365 \mathrm{mg}$ :
$1 \mathrm{mg}=10^{-3} \mathrm{~g}$
$25365 \mathrm{mg}=2.5365 \times 10^{4} \times 10^{-3} \mathrm{~g}$
Since,
$1 \mathrm{~g}=10^{-3} \mathrm{~kg}$
$2.5365 \times 10^{1} \mathrm{~g}=2.5365 \times 10^{-1} \times 10^{-3} \mathrm{~kg}$
$\therefore 25365 \mathrm{mg}=2.5365 \times 10^{-2} \mathrm{~kg}$