Question:
Divide −72a4b5c8 by −9a2b2c3.
Solution:
$\frac{-72 a^{4} b^{5} c^{8}}{-9 a^{2} b^{2} c^{3}}$
$=\frac{-72 \times a \times a \times a \times a \times b \times b \times b \times b \times b \times c \times c \times c \times c \times c \times c \times c \times c}{-9 \times a \times a \times b \times b \times c \times c \times c}$
$=8 a^{(4-2)} b^{(5-2)} c^{(8-3)}$
$=8 a^{2} b^{3} c^{5}$
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