Define the following

Question:

Divide −72a4b5c8 by −9a2b2c3.

Solution:

$\frac{-72 a^{4} b^{5} c^{8}}{-9 a^{2} b^{2} c^{3}}$

$=\frac{-72 \times a \times a \times a \times a \times b \times b \times b \times b \times b \times c \times c \times c \times c \times c \times c \times c \times c}{-9 \times a \times a \times b \times b \times c \times c \times c}$

$=8 a^{(4-2)} b^{(5-2)} c^{(8-3)}$

$=8 a^{2} b^{3} c^{5}$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now