Question:
Divide 6x3y2z2 by 3x2yz.
Solution:
$\frac{6 x^{3} y^{2} z^{2}}{3 x^{2} y z}$
$=\frac{6 \times x \times x \times x \times y \times y \times z \times z}{3 \times x \times x \times y \times z}$
$=2 x^{(3-2)} y^{(2-1)} z^{(2-1)}$
$=2 x y z$
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