**Question:**

Draw a trapezium *ABCD* in which *AB*||*DC*, *AB* = 7 cm, *BC *= 5 cm, *AD *= 6.5 cm and ∠*B* = 60°.

**Solution:**

Steps of construction:

Step1: Draw $A B$ equal to $7 \mathrm{~cm}$.

Step2: Make an angle, $\angle A B X$, equal to $60^{\circ}$.

Step3: With $B$ as the centre, draw an arc of $5 \mathrm{~cm}$. Name that point as $C$. Join $B$ and $C$.

Step4: $A B \| D C$

$\therefore \angle A B X+\angle B C Y=180^{\circ}$

$\Rightarrow \angle B C Y=180^{\circ}-60^{\circ}=120^{\circ}$

Draw an angle, $\angle B C Y$, equal to $120^{\circ}$.

Step4: With *A* as the centre, draw an arc of length 6.5 cm, which cuts *CY*. Mark that point as *D*.

Step5: Join *A *and* D*.

Thus, *ABCD* is the required trapezium.

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