Duration of sunshine(in hours) in Amritsar for first 10 days of August 1997 as reported
Duration of sunshine(in hours) in Amritsar for first 10 days of August 1997 as reported by the Meterological Department are given as follows : 9.6 , 5.2 , 3.5 , 1.5 , 1.6 , 2.4 , 2.6 , 8.4 , 10.3 , 10.9
1. Find the mean $\overline{\mathrm{X}}$
2. Verify that $\sum_{i=1}^{10}\left(x^{i}-\bar{X}\right)=0$
Duration of sunshine (in hours ) for 10 days are = 9.6 , 5.2 , 3.5 , 1.5 , 1.6 , 2.4 , 2.6 , 8.4 , 10.3 , 10.9
(i) Mean $X=\frac{\text { Sum of numbers }}{\text { Total numbers }}$
$=\frac{9.6+5.2+3.5+1.5+1.6+2.4+2.6+8.4+10.3+10.9}{10}$
= 56/10 = 5.6
(ii) L.H.S $=\sum_{i=1}^{10}\left(x^{i}-\bar{X}\right)=0$
$=\left(\mathrm{x}_{1}-\overline{\mathrm{x}}\right)+\left(\mathrm{x}_{2}-\overline{\mathrm{x}}\right)+\left(\mathrm{x}_{3}-\overline{\mathrm{x}}\right)+\cdots+\left(\mathrm{x}_{10}-\overline{\mathrm{x}}\right)$
= (9.6 − 5.6) + (5.2 − 5.6) + (3.5 − 5.6) + (1.5 − 5.6) + (1.6 − 5.6) + (2.4 − 5.6) + (2.6 − 5.6) + (8.4 − 5.6) + (10.3 − 5.6) + (10.9 − 5.6)
= 4 – 0.4 – 2.1 – 4.1 – 4 – 3.2 – 3 + 2.8 + 4.7 + 5.3
= 16.8 – 16.8 = 0
= R.H.S