# Each side of an equilateral triangle measure 8 cm.

Question:

Each side of an equilateral triangle measure 8 cm. The area of the triangle is

(a) $8 \sqrt{3} \mathrm{~cm}^{2}$

(b) $16 \sqrt{3} \mathrm{~cm}^{2}$

(c) $32 \sqrt{3} \mathrm{~cm}^{2}$

(d) $48 \mathrm{~cm}^{2}$

Solution:

(b) $16 \sqrt{3} \mathrm{~cm}^{2}$

Area of equilateral triangle $=\frac{\sqrt{3}}{4} \times(\text { Side })^{2}$

$=\frac{\sqrt{3}}{4} \times(8)^{2}$

$=\frac{\sqrt{3}}{4} \times 64$

$=16 \sqrt{3} \mathrm{~cm}^{2}$