Electric field in a plane

Question:

Electric field in a plane electromagnetic wave is given by $\mathrm{E}=50 \sin \left(500 \mathrm{x}-10 \times 10^{10} \mathrm{t}\right) \mathrm{V} / \mathrm{m}$ The velocity of electromagnetic wave in this medium is :

(Given $\mathrm{C}=$ speed of light in vacuum)

  1. $\frac{3}{2} \mathrm{C}$

  2. $\mathrm{C}$

  3. $\frac{2}{3} \mathrm{C}$

  4. $\frac{C}{2}$


Correct Option: , 3

Solution:

$\mathrm{V}=\frac{\omega}{\mathrm{K}}=\frac{10 \times 10^{10}}{500}=2 \times 10^{8}$

$\mathbf{V}=\frac{2 \mathrm{C}}{3}$

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