Question:
Factorise:
16x5 − 144x3
Solution:
We have:
$16 x^{5}-144 x^{3}=16 x^{3}\left(x^{2}-9\right)$
$=16 x^{3}\left\{(x)^{2}-(3)^{2}\right\}$
$=16 x^{3}(x+3)(x-3)$
$\therefore 16 x^{5}-144 x^{3}=16 x^{3}(x+3)(x-3)$
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