Question:
Factorise:
3x5 − 48x3
Solution:
We have:
$3 x^{5}-48 x^{3}=3 x^{3}\left(x^{2}-16\right)$
$=3 x^{3}\left\{(x)^{2}-(4)^{2}\right\}$
$=3 x^{3}(x+4)(x-4)$
$\therefore 3 x^{5}-48 x^{3}=3 x^{3}(x+4)(x-4)$
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