Question:
Factorize each of the following algebraic expressions:
6(a + 2b) −4(a + 2b)2
Solution:
$6(a+2 b)-4(a+2 b)^{2}$
$=[6-4(a+2 b)](a+2 b) \quad[$ Taking $(a+2 b)$ as the common factor $]$
$=2[3-2(a+2 b)](a+2 b) \quad\{$ Taking 2 as the common factor of $[6-4(a+2 b)]\}$
$=2(3-2 a-4 b)(a+2 b)$
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