# Find the 20th term in the following sequence whose nth term is

Question:

Find the 20th term in the following sequence whose nth term is $a_{n}=\frac{n(n-2)}{n+3} ; a_{20}$

Solution:

Substituting $n=20$, we obtain

$a_{20}=\frac{20(20-2)}{20+3}=\frac{20(18)}{23}=\frac{360}{23}$