Find the area enclosed by the given figure ABCDEF as per dimensions given herewith.

Question:

Find the area enclosed by the given figure ABCDEF as per dimensions given herewith.

Solution:

Area enclosed by the given figure $=$ (Area of trapezium FEDC) $+$ (Area of square $\mathrm{ABCF}$ )

$=\left[\left\{\frac{1}{2} \times(6+20) \times 8\right\}+(20 \times 20)\right] \mathrm{cm}^{2}$

$=(104+400) \mathrm{cm}^{2}$

$=504 \mathrm{~cm}^{2}$

Hence, the area enclosed by the figure is $504 \mathrm{~cm}^{2}$.

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now