Question:
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm.
Solution:
Area of a trapezium $=\frac{1}{2} \times($ Sum of parallel sides $) \times($ Distance between them $)$
$=\left\{\frac{1}{2} \times(24+20) \times 15\right\} \mathrm{cm}^{2}$
$=\left(\frac{1}{2} \times 44 \times 15\right) \mathrm{cm}^{2}$
$=(22 \times 15) \mathrm{cm}^{2}$
$=330 \mathrm{~cm}^{2}$
Hence, the area of the trapezium is $330 \mathrm{~cm}^{2}$.