Question:
Find the area of the region bounded by the curves $y=x^{2}+2, y=x, x=0$ and $x=3$
Solution:
The area bounded by the curves, $y=x^{2}+2, y=x, x=0$, and $x=3$, is represented by the shaded area OCBAO as
Then, Area OCBAO = Area ODBAO – Area ODCO
$=\int_{0}^{3}\left(x^{2}+2\right) d x-\int_{0}^{3} x d x$
$=\left[\frac{x^{3}}{3}+2 x\right]_{0}^{3}-\left[\frac{x^{2}}{2}\right]_{0}^{3}$
$=[9+6]-\left[\frac{9}{2}\right]$
$=15-\frac{9}{2}$
$=\frac{21}{2}$ units
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