Find the area of the triangle


Find the area of the triangle whose vertices are (-8,4), (-6,6) and (- 3, 9).


Given that, the vertices of triangles

Let $\quad\left(x_{1}, y_{1}\right) \rightarrow(-8,4)$

$\left(x_{2}, y_{2}\right) \rightarrow(-6,6)$

and $\quad\left(x_{3}, y_{3}\right) \rightarrow(-3,9)$

We know that, the area of triangle with vertices $\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)$ and $\left(x_{3}, y_{3}\right)$


$\therefore$ $=\frac{1}{2}[-8(6-9)-6(9-4)+(-3)(4-6)]$




Hence, the required area of triangle is 0.

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