Find the compound interest on Rs 1000 at the rate of

Given:

$\mathrm{P}=\mathrm{Rs} 1,000$

$\mathrm{R}=8 \%$ p. a.

$\mathrm{n}=1.5$ years

We know that:

$\mathrm{A}=\mathrm{P}\left(1+\frac{\mathrm{R}}{200}\right)^{2 \mathrm{n}}$

$=1,000\left(1+\frac{8}{200}\right)^{3}$

$=1,000(1.04)^{3}$

$=\mathrm{Rs} 1,124.86$

Now,

$\mathrm{CI}=\mathrm{A}-\mathrm{P}$

$=\mathrm{Rs} 1,124.86-\mathrm{Rs} 1,000$

$=\mathrm{Rs} 124.86$